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\begin{align}
{1 \over ( x+1 ) ( x+4 ) }
&=
{1 \over ( 3 ) }
\left\{ {1 \over ( x+1 ) }-{1\over ( x+4 ) } \right\} \\
\\
{1 \over ( x-3 ) ( x+3 ) }
&=
{1 \over ( 6 ) }
\left\{ {1 \over ( x-3 ) }-{1\over ( x+3 ) } \right\} \\
\\
{1 \over ( x-1 ) ( x-6 ) }
&=
{1 \over ( -5) }
\left\{ {1 \over ( x-1) }-{1\over ( x-6 ) } \right\} \\
または\\
&=
{1 \over ( 5) }
\left\{ {1 \over ( x-6) }-{1\over ( x-1 ) } \right\} \\
\end{align}
分数の掛け算は、分数の引き算に直せますね。
では前回の復習
- 積分しなさい
(1)
$\displaystyle
\int_{x=0}^{x=1} {2x+7 \over x^2+7x+10} \, dx
$
(2)
$\displaystyle
\int_{x=0}^{x=1} {1 \over x^2+7x+10} \, dx
$
-
出来たらめくる
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